If a sewage spill was observed running at 6 gallons per minute for 27 minutes, how much sewage went uncaptured?

To determine the total amount of sewage that went uncaptured during the observed spill, you need to multiply the rate at which the sewage was spilling by the duration of the spill.

In this case, the sewage was observed spilling at a rate of 6 gallons per minute for a total of 27 minutes. Performing the calculation:

6 gallons per minute × 27 minutes = 162 gallons.

Thus, the correct answer of 162 gallons represents the total volume of sewage that went uncaptured during the spill. Understanding this calculation is essential, as it reflects a fundamental concept in wastewater management—being able to quantify spills quickly helps mitigate their impact and informs response strategies in real-time scenarios.