If sewage is spewing at a rate of 166 gallons per minute for 22 minutes, how many total gallons overflow?

To determine the total gallons of sewage overflowing, you need to multiply the rate of flow by the time period during which the overflow occurs. In this case, if sewage is spilling at a rate of 166 gallons per minute for 22 minutes, the calculation is as follows:

Total gallons = Rate (gallons per minute) × Time (minutes)

Total gallons = 166 gallons/minute × 22 minutes

Total gallons = 3,652 gallons

Consequently, the total volume of overflow during this period is 3,652 gallons. This means that while it may initially seem that an option suggesting significantly higher values could be correct, the correct calculation demonstrates a clear and accurate volume of overflow occurring within the stated time frame. It is essential to perform the multiplication accurately to reach the correct total, ensuring clarity on how the flow rate and time correlate to the volume of overflow.